(.01x^2)-7x+600=0

Solution for (.01x^2)-7x+600=0 equation:

(.01x^2)-7x+600=0

We add all the numbers together, and all the variables

-7x+(.01x^2)+600=0

We get rid of parentheses

.01x^2-7x+600=0

a = .01; b = -7; c = +600;
Δ = b2-4ac
Δ = -72-4·.01·600
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*.01}=\frac{2}{0.02}
=100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*.01}=\frac{12}{0.02}
=600
$